- #1

- 65

- 3

- Homework Statement
- Finding ##\Delta v## from an ##a-t## graph

- Relevant Equations
- Area under graph methods

The variation with time t of the acceleration a of an object is shown

What is the change in velocity of the object from ##t=0## to ##t=6##?

A. ##6ms^{-1}##

B. ##8ms^{-1}##

C. ##10ms^{-1}##

D. ##14ms^{-1}##

So apparently the answer is B, which I am having trouble reconciling.

Using methods of areas I get ##2ms^{-1}## for the first ##2s## and ##8ms^{-1}## for the last ##4s##. Total ##\Delta v=10ms^{-1}## right?

I don't think there should be much more calculation needed for this question so I assume my interpretation is what is off.

I've tried doing this with calculus and I get the same answer, which isn't a surprise. I even tried assuming that ##v=0## at the start and built it up from there, which still gives me a ##\Delta v## of ##10ms^{-1}##.

I'm a bit dumbfounded. Can anyone comment?

What is the change in velocity of the object from ##t=0## to ##t=6##?

A. ##6ms^{-1}##

B. ##8ms^{-1}##

C. ##10ms^{-1}##

D. ##14ms^{-1}##

So apparently the answer is B, which I am having trouble reconciling.

Using methods of areas I get ##2ms^{-1}## for the first ##2s## and ##8ms^{-1}## for the last ##4s##. Total ##\Delta v=10ms^{-1}## right?

I don't think there should be much more calculation needed for this question so I assume my interpretation is what is off.

I've tried doing this with calculus and I get the same answer, which isn't a surprise. I even tried assuming that ##v=0## at the start and built it up from there, which still gives me a ##\Delta v## of ##10ms^{-1}##.

I'm a bit dumbfounded. Can anyone comment?