Finding the Constant in a Separable Differential Equation

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SUMMARY

The discussion centers on solving the separable differential equation \(\frac{dy}{dx} = \frac{1+\sqrt{x-2}}{1+2y}\). The user has simplified the equation to \(y + y^2 = x + \frac{2}{3}(x-2)^{\frac{3}{2}} + C_1\). The key point is that without an initial condition, the constant \(C_1\) remains undetermined. To find \(C_1\), the user must either have an initial condition or proceed with solving the equation as a quadratic.

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Homework Statement


[tex]\frac{dy}{dx} = \frac{1+\sqrt{x-2}}{1+2y}[/tex]

I have solved the equation down too

y + y2 = x + (2/3)(x-2)(3/2) + C1


I am not sure where to go from here... Do I solve for C1 and then plug it back into the equation and solve it as a quadratic or just solve it as a quadratic?
 
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If you have an initial condition, you can use it to solve for C whenever you want. Otherwise there's no way of determining its value.
 

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