Finding the diagonal of an irregular quadrilateral

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SUMMARY

The discussion focuses on proving the relationship in an irregular quadrilateral ABCD, where the sides are defined as AB=a, BC=b, CD=c, DA=d, and the diagonal AC is x. The key equation to prove is (ab+cd)x²=(ac+bd)(ad+bc), utilizing the cosine formula c² = a² + b² - 2abcosθ. Participants suggest applying the cosine formula twice, once for triangle ABC and once for triangle ADC, to establish a connection between the two expressions involving x.

PREREQUISITES
  • Understanding of the cosine formula in trigonometry
  • Knowledge of properties of irregular quadrilaterals
  • Familiarity with angle relationships in polygons
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the cosine rule in depth, particularly in the context of non-right triangles
  • Explore the properties of irregular quadrilaterals and their diagonals
  • Practice solving geometric proofs involving multiple triangles
  • Learn about angle sum properties in polygons
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Students studying geometry, particularly those tackling problems involving irregular quadrilaterals, as well as educators looking for examples of geometric proofs.

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Homework Statement


In an irregular quadrilateral ABCD, the length of all sides are AB=a BC=b CD=c DA=d and the length of the diagonal AC is x. Angle ABC + angle ADC = 180

prove that (ab+cd)x2=(ac+bd)(ad+bc)

Homework Equations



Cosine formula c2 = a2 + b2 - 2abcosθ

The Attempt at a Solution


I really have no idea how to start
 
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Use the cosine formula, c^2= a^2+ b^2- 2abcos(C), with x as "c", sides AB and BC as "a" and "b", and angle ABC as angle "C". Then do the same with x as "c" again but AD and BD as "a" and "b", and angle ADC as angle "C". Of course, the "x" in both of those is the same so they can be set equal.
 

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