Prove that ME=MC in a Circle Geometry ABCD

Lukybear · Oct 5, 2010

ABCD is a cyclic quadrilateral. The diagonals AC and BD intersect at right angles at E. M is the midpoint of CD. ME produced meets AB at N.

Show that ME = MC

berkeman · Oct 6, 2010

Lukybear said:

ABCD is a cyclic quadrilateral. The diagonals AC and BD intersect at right angles at E. M is the midpoint of CD. ME produced meets AB at N.

Show that ME = MC

What are your thoughts on how to proceed?

Lukybear · Oct 7, 2010

Nvm, I've found solution. Thxs.

Prove that ME=MC in a Circle Geometry ABCD

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Prove that ME=MC in a Circle Geometry ABCD

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