Lukybear Messages 8 Reaction score 0 Thread starter Oct 5, 2010 #1 ABCD is a cyclic quadrilateral. The diagonals AC and BD intersect at right angles at E. M is the midpoint of CD. ME produced meets AB at N. Show that ME = MC Attachments Circle Geo Independent.jpg 11.7 KB · Views: 484 Last edited by a moderator: Oct 6, 2010
ABCD is a cyclic quadrilateral. The diagonals AC and BD intersect at right angles at E. M is the midpoint of CD. ME produced meets AB at N. Show that ME = MC
berkeman Admin Messages 69,677 Reaction score 25,416 Oct 6, 2010 #2 Lukybear said: ABCD is a cyclic quadrilateral. The diagonals AC and BD intersect at right angles at E. M is the midpoint of CD. ME produced meets AB at N. Show that ME = MC What are your thoughts on how to proceed?
Lukybear said: ABCD is a cyclic quadrilateral. The diagonals AC and BD intersect at right angles at E. M is the midpoint of CD. ME produced meets AB at N. Show that ME = MC What are your thoughts on how to proceed?