Prove that ME=MC in a Circle Geometry ABCD

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Lukybear
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ABCD is a cyclic quadrilateral. The diagonals AC and BD intersect at right angles at E. M is the midpoint of CD. ME produced meets AB at N.

Show that ME = MC
 

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Lukybear said:
ABCD is a cyclic quadrilateral. The diagonals AC and BD intersect at right angles at E. M is the midpoint of CD. ME produced meets AB at N.

Show that ME = MC

What are your thoughts on how to proceed?
 
Nvm, I've found solution. Thxs.