Finding the displacement of a object as viewed through water

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  • Thread starter Thread starter Krishna0703
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    Displacement Water
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Discussion Overview

The discussion revolves around calculating the apparent displacement of an object submerged in water, specifically focusing on the effects of refraction as viewed from above the water's surface. Participants explore the relevant formulas and conditions that apply to this scenario.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant inquires about the formula to calculate the displacement of an object viewed through water and asks about applicable conditions.
  • Another participant references a resource that provides a formula related to the apparent depth and real depth, suggesting that the mathematics is straightforward but challenging in practice.
  • A different participant mentions the relevance of the refractive index in determining the apparent position of the object.
  • Further, a participant notes that understanding Snell's Law could help derive the necessary formulas for this situation.

Areas of Agreement / Disagreement

Participants express differing views on the best approach to calculate the displacement, with some referencing specific formulas and others emphasizing the importance of understanding underlying principles like Snell's Law. No consensus is reached on a single method or formula.

Contextual Notes

Participants do not fully clarify the assumptions or conditions under which the formulas apply, nor do they resolve the mathematical steps involved in deriving the necessary calculations.

Krishna0703
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hi everybody, suppose we are viewing an object in a pool whereby the object is actually at the bottom of the pool, ...so it will appear as if it has been displaced. what formula can we use to calculate the displacement of the object...??
are there any conditions applicable..help me with this detail please
 
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Are you a frustrated harpoon fisherman? I have spent ages trying to spear fish from the side of a boat. The Maths is not hard -
http://www.physicstutorials.org/home/optics/refraction-of-light/apparent-depth-real-depth" gives you the formula but it's hard to work it out on the fly and amidst the excitement of a massive Grey Mullett going past.
 
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nah man, there do have a formula related to the refractive index...
 
It's on that link for you to use at your leisure. The formula gives both the new angle and the new height. But, if you know Snell's Law, you should be able to derive it for yourself. At least, their derivation makes easy sense.

I'll get back to my fishing when my future son in law buys a new harpoon to replace the one he chucked over the side by mistake.
 

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