Finding the Distance Fallen and Frequency Shift with Doppler's Effect

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SUMMARY

The discussion focuses on calculating the distance fallen by a tuning fork vibrating at 514 Hz, which accelerates at 9.80 m/s² until waves of frequency 487 Hz reach the release point. The observer frequency formula, fobs = [1/((1+u)/343)]*fsource, was applied, yielding an upward velocity (u) of 19.01 m/s. To determine the distance fallen, the next step involves using motion equations to find the fall time and subsequently the distance fallen during that time.

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  • Basic knowledge of kinematics, specifically motion equations
  • Familiarity with frequency and wave concepts
  • Ability to perform calculations involving acceleration and velocity
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  • Study the derivation and application of the Doppler Effect formula
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Dopplers Effect, Please Help!

Homework Statement



A tuning fork vibrating at 514 Hz falls from rest and accelerates at 9.80 m/s2. How far below the point of release is the tuning fork when waves of frequency of 487 Hz reach the release point? (Take the speed of sound in air to be 343 m/s.)

Homework Equations





The Attempt at a Solution



fobs=[1/((1+u)/343)]*fsource

487=[1/((1+u)/343)]*514
u=19.01 m/s

That's as far as I got. I'm not sure what to do next or if I'm even on the right track. Any help would be appreciated. Thanks
 
Last edited:
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The formula looks a little odd, but I think the 19 m/s is correct.
Next step is to use motion formulas to find out how far it has fallen to acquire that speed. You might want to find the fall time first.
 

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