What distance is required to stop a car going 90km/h if the car can stop with an acceleration of -6.0m/s2?
a = v2-v1/t
d = (v1+v2/2)t
The Attempt at a Solution
I'm thinking first we have to solve for t. Which would be the speed divided by acceleration, which is -0.36 km/h^2 over 80km/h which is 0.0045 hours.
Now to solve for distance, it would be 80km/2 x 0.0045
Which leaves me with 0.18 which is completely wrong because the answer is supposed to be 41 m.
Help please? Thank you.