Finding the Dot Product of Vector A & B

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SUMMARY

The discussion centers on calculating the dot product of two vectors, A and B, with magnitudes of 5.00 units and 9.00 units, respectively, and an angle of 49° between them. The correct formula for the dot product is A·B = (magnitude A)(magnitude B)cos(θ), where θ is the angle between the vectors. The user initially attempted to multiply the vectors incorrectly, leading to confusion. The proper application of the formula yields the scalar product, which is essential for vector analysis.

PREREQUISITES
  • Understanding of vector notation and operations
  • Familiarity with trigonometric functions, specifically cosine
  • Knowledge of scalar and vector products
  • Basic principles of physics related to forces and magnitudes
NEXT STEPS
  • Study the concept of vector addition and subtraction
  • Learn about the geometric interpretation of the dot product
  • Explore applications of dot products in physics, such as work done by a force
  • Investigate the relationship between dot products and projections of vectors
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Students in physics or mathematics, educators teaching vector analysis, and anyone seeking to understand the application of dot products in real-world scenarios.

chocolatelover
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Homework Statement


Vector A has a magnitude of 5.00 units, and vector B has a magnitude of 9.00 units. The two vectors make an angle of 49° with each other. Find (vector A)(vector B)


Homework Equations





The Attempt at a Solution



(5i+0j)(0i+9j)=
(5N)(0m)+(0N)(9m)=

square root (5^2+0^2)
=5N

Could someone please tell me if this is correct and if not could someone show me how to do it?

Thank you very much
 
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chocolatelover said:
Find (vector A)(vector B)

(vector A)(vector B)?

This notation does not mean anything. Possibly, you mean the scalar product A.B?

How did you utilize the 49 deg given in the problem?

A.B = (magnitude A)(magnitude B)cos \theta, where \theta is the angle between A and B.

Take my advice given in the other post.
 
Thank you

Regards
 

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