Finding dot product, cross, and angle between 2 vectors

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Homework Help Overview

The discussion revolves around finding the dot product, cross product, and angle between two vectors defined in three-dimensional space. Vector A is situated in the yz plane, while Vector B is in the xz plane, with both vectors having specified angles and magnitudes.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to express the vectors in unit vector notation and are questioning the relevance of the positive z component in their calculations. There is also a focus on understanding how to incorporate the z component into the dot and cross product calculations.

Discussion Status

Some participants have offered insights about the importance of sketching the vectors to clarify their orientation in space. There is an ongoing exploration of how to derive the components needed for the calculations, but no consensus has been reached on the exact setup or approach.

Contextual Notes

Participants are navigating the implications of the vectors being in three-dimensional space and the significance of the angles and positive components as they relate to their calculations. There is an acknowledgment of the complexity involved in visualizing and calculating the products of these vectors.

PAstudent
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Homework Statement


[/B]
Vector A lies in the yz plane 63.0 degrees from the +y axis, has a positive z component, and has a magnitude 3.20 units. Vector B lies in the xz 48.0 degrees from the +x axis, has positive z component, and has magnitude 1.40 units.

a) find A dot B
b) find A x B
c) the angle between A and B

Homework Equations


dot product and cross product [/B]

The Attempt at a Solution



What I am trying is to put them in unit vector notation like:
A= axi+ayj so A= [3.20cos(63.0)]i+[3.20sin(63.0)] and then the same for vector B

Then once I have those components I could easily do dot and cross product. My question is what does that "has a positive z component " have to do with anything? And is my setup correct?[/B]
 
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PAstudent said:

Homework Statement


[/B]
Vector A lies in the yz plane 63.0 degrees from the +y axis, has a positive z component, and has a magnitude 3.20 units. Vector B lies in the xz 48.0 degrees from the +x axis, has positive z component, and has magnitude 1.40 units.

a) find A dot B
b) find A x B
c) the angle between A and B

Homework Equations


dot product and cross product [/B]

The Attempt at a Solution



What I am trying is to put them in unit vector notation like:
A= axi+ayj so A= [3.20cos(63.0)]i+[3.20sin(63.0)] and then the same for vector B

Then once I have those components I could easily do dot and cross product. My question is what does that "has a positive z component " have to do with anything? And is my setup correct?[/B]
For example, vector B could make an angle of 48° above or below the +x-axis. The "positive z-component" tells you which side of the +x-axis to draw this vector.

I find in these cases making a simple sketch usually clarifies things a bit.
 
So would there be a z hat in the calculations of the dot and cross or does it just tell you the location of the vector? Because I am still trying to figure out how to find the i and j to be able to find the products
 
PAstudent said:
So would there be a z hat in the calculations of the dot and cross or does it just tell you the location of the vector? Because I am still trying to figure out how to find the i and j to be able to find the products
It seems you have three-dimensional vectors here, but I haven't sketched them out or anything. You'll have to work thru the verbal descriptions, and make some sketches as I suggested.
 

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