Your above calculations kinda worry me. Is this intermediate step something you are explicitly told to calculate? If so, I don't think it's correct: According to my calculations, (total) energy and momentum are not conserved in your calculations (as they should be). If you are not required to perform this intermediate step, then I don't think it's necessary.Aaron7 said:Mass M orginally formed by mass m traveling at v=3c/5 hitting a stationary mass m.
This gives M v=c/3 and M=3m/√2.
The process involves using the principles of conservation of energy and momentum to calculate the energies of the photons. This can be done by analyzing the decay products of the travelling mass and using equations such as E=mc^2 and p=mv.
The energies of the photons can be determined by measuring their wavelengths or frequencies, as well as considering the masses and velocities of the particles involved in the decay. These values can then be used in the equations E=hc/λ or E=hf to calculate the energies.
The energies of the photons can be affected by the mass and velocity of the travelling mass, as well as any interactions or collisions with other particles during the decay process. Additionally, the direction and angle of emission of the photons can also impact their energies.
Yes, it is possible to calculate the energies of the photons accurately using the principles of conservation of energy and momentum. However, there may be uncertainties or errors in the measurements of the decay products that can affect the accuracy of the calculations.
Finding the energies of the photons can provide important information about the properties and interactions of particles involved in the decay process. This can help further our understanding of fundamental laws and principles in physics, and also has practical applications in fields such as medical imaging and energy production.