Finding the equation of the circle given two points and a tangent line

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SUMMARY

The discussion focuses on finding the equation of a circle that passes through the point (3,-2) and is tangent to the line y=3x+5 at the point (-1,2). To solve this, the distance formula d= |mx0+b-y0|/sqrt(1+m^2) is utilized to determine the radius, while the standard form of the circle's equation (x-h)²+(y-k)²=r² is applied to derive the final equation. The center of the circle can be found using calculus or by constructing a perpendicular line to the tangent at the point of tangency.

PREREQUISITES
  • Understanding of the distance formula in coordinate geometry
  • Familiarity with the standard form of a circle's equation
  • Basic knowledge of calculus concepts related to slopes and tangents
  • Ability to construct perpendicular lines in a Cartesian plane
NEXT STEPS
  • Study the distance formula in detail and its applications in geometry
  • Learn how to derive the equation of a circle from given points
  • Explore calculus techniques for finding slopes and tangents
  • Practice constructing perpendicular lines and finding intersection points
USEFUL FOR

Students studying geometry, particularly those tackling problems involving circles, tangents, and calculus concepts. This discussion is beneficial for anyone looking to enhance their problem-solving skills in coordinate geometry.

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Homework Statement


Find the equation of the circle that passes through the point (3,-2) and tangent to the line y=3x+5 at (-1,2). Answer in standard form.


Homework Equations


d= |mx0+b-y0|
____________
sqrt(1+m2

is needed to find the radius of the circle
(x-h)2+(y-k)2=r2 is needed to find the equation of the circle.

The Attempt at a Solution



I haven't attempted a solution per se, but I do know that I need to find the center of the circle. However I don't see a way to find the center of a circle.
 
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You need to figure out h, k, and r, right? Three unknowns. Here are a couple of suggestions, depending on whether you know any calculus.

If you know calculus, you can get three equations in the three unknowns by using the fact that your two given points must work in the equation, and the slope of the circle must equal the slope of the tangent line where they touch.

If you can't use calculus, write the equation of the line perpendicular to the tangent line at (-1,2) and find the point on that line that is equidistant from your two given points. That will be your center.
 

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