Finding the equilibrium state from force diagrams

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Ivan Antunovic
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Problems stated in attached pictures.So could someone explain me what am I doing wrong here this is solution for the example a) .
I tried it twice and I am getting wrong results.

Thanks in advance.
 
Attachments
  • Text problem with three beam diagrams labeled a, b and c, each showing points A and B at beam ends with a force F applied; GIVEN values F1 = 2000.0 N, a = 10.0 m, b = 4.0 m, alpha = 45 degrees, followed by printed solutions.
    STATIKA.jpg
    32.1 KB · Views: 446
  • Handwritten free-body diagram of a rigid bar with pins A and B, a force F at 45 degrees with components F sin45 and F cos45, reactions F_Ax, F_Ay and F_B, dimensions a and b, plus equilibrium equations and solution steps written beside it.
    DSC_0667.JPG
    26.5 KB · Views: 389
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Sorry for the 2nd picture in my first post,hope it's not rotated this time.
 
Attachments
  • Handwritten statics solution: beam diagram with supports A and B, forces F1 at 45 degrees, distances a and b, then equilibrium equations and computed values of F_B and F_Ay.
    DSC_0667.JPG
    15.7 KB · Views: 396
To get the given answers in the first question, you would need to use a=4 and b=6, or something equivalent.
 
haruspex said:
To get the given answers in the first question, you would need to use a=4 and b=6, or something equivalent.

First of all thank you for replay.

Thank you man so much.I was really confused whole Sunday trying to figure out if I was doing something wrong. Now I've gotten correct answers for both cases a) ,b) and c).

I have one more question.I took intuitively an angle between Forces Fb and Fby to be 45 degrees but I am trying to figure it out mathematically.
Hand-drawn free-body diagram of a point B on an inclined surface at 45 degrees, with force F_B along the surface normal direction, components F_Bx horizontal and F_By vertical, and point A to the left on a horizontal line.

images upload
 
Ivan Antunovic said:
First of all thank you for replay.

Thank you man so much.I was really confused whole Sunday trying to figure out if I was doing something wrong. Now I've gotten correct answers for both cases a) ,b) and c).

I have one more question.I took intuitively an angle between Forces Fb and Fby to be 45 degrees in c) example but I am trying to figure it out mathematically.
Hand-drawn force diagram: a horizontal line from point A to joint B, with force F_B along a 45-degree line and its components F_Bx and F_By, plus two 45-degree angle marks against a hatched support.

images upload
 
Ivan Antunovic said:
First of all thank you for replay.

Thank you man so much.I was really confused whole Sunday trying to figure out if I was doing something wrong. Now I've gotten correct answers for both cases a) ,b) and c).

I have one more question.I took intuitively an angle between Forces Fb and Fby to be 45 degrees but I am trying to figure it out mathematically.
Hand-drawn free-body diagram of a point B on a 45-degree inclined surface with force vectors F_B, F_By and F_Bx, a horizontal line to point A, and 45-degree angle marks.

http://postimage.org/
I assume this is in relation to c.
The question as given is not clear enough to obtain an answer. It would be better if it showed B as a flat plane at 45 degrees, stated to be frictionless. In that case you would deduce that the normal force is also at 45 degrees to the vertical.
 
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haruspex said:
I assume this is in relation to c.
The question as given is not clear enough to obtain an answer. It would be better if it showed B as a flat plane at 45 degrees, stated to be frictionless. In that case you would deduce that the normal force is also at 45 degrees to the vertical.
Yes I was talking about c example.
There is actually no way to find Fa x and Fbx unless assuming that the angle is 45 degrees,since both of those forces go through point A and B so their torque is zero at those points.
 
I have one more question if you could check if I was doing everything fine in this task.Text goes:

The tops of an equilateral triangular plate , where the side length is a = 100 mm and where forces are operating which are F1 = F2 = F3 = 2 kN and torque M = 0.1 kNm .
Thickness and weight plates ignore . Reduce the set and force a default torque M at point A.

Handwritten notes on paper showing a force diagram of an equilateral triangle with forces F1, F2 and F3 and a torque M at vertex A, followed by component equations and a resultant magnitude calculation.

http://postimage.org/

Handwritten statics sketch of an equilateral triangle ABC with a height line and angle marked, followed by moment equations for MA and the resulting value 0.173 kNm, and a free-body diagram of the plate showing forces F1, F2, F3, torque M and point A.

http://postimage.org/app.php

thank you again for your answer
 
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Ivan Antunovic said:
The tops of an equilateral triangular plate , where the side length is a = 100 mm and where forces are operating which are F1 = F2 = F3 = 2 kN and torque M = 0.1 kNm .
Thickness and weight plates ignore . Reduce the set and force a default torque M at point A.
I take it from your diagram that the three forces are all in the plane of the plate and act as shown. But I don't understand the last sentence. What does it mean? Is that the exact wording?
 
I tried to translate it well from my language,but google translate failed this time so I will try to explainit,it is required to translate all forces and given torque at point A
 
Ivan Antunovic said:
I tried to translate it well from my language,but google translate failed this time so I will try to explainit,it is required to translate all forces and given torque at point A
The three forces are each directed along a side of the triangle from their points of application, yes? Rather than leap into converting each force into X and Y components, think about the line of action of F3 and what that implies for its moment about A.

By the way, your images are not easy to read. The writing is a little faint, and I see your shadow on them. It is much easier for others if you take the trouble to type your working in. In particular, it makes it much easier to quote and draw attention to specific lines of algebra. The ability to upload images is really for textbook extracts and diagrams.