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## Homework Statement

160g of steam at 100°C is added to 1000 g of ice at 0°C. What is the equilibrium temperature of the mixture? Assume the container has a negligible heat capacity.

## Homework Equations

**Qloss+Qgain=0;[m*c(delta T)] + [m*c(delta T)] = 0**

## The Attempt at a Solution

i have the final answer which is

**19.3 degree Celsius**but i dunno how to get it., i used the formula of

**Qloss+Qgain=0;[m*c(delta T)] + [m*c(delta T)] = 0**. but my final answer is not 19.3.., can you please help me? what formula will i need to use? do i need to consider the latent heat of vaporization and fusion?if so, what should be the formula?

this is my solution;

Qloss(steam) + Qgain (ice) = 0

m*C (ΔT) + m*C (ΔT) = 0

160g*0.48cal/g C° (t-100°C) + 1000g*0.50cal/g C°(t-0) = 0

76.8 (t-100) + 500 (t-0) = 0

76.8 t - 7680 + 500 t = 0

576.8 t / 576.8 = 7680/576.8

**t = 13.3 °C**