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Finding the exact value for period in radians

  1. Mar 17, 2010 #1
    1. The problem statement, all variables and given/known data
    What is the exact period of the function f(x)= 6 sin (4x+pi)
    = a sin (b)

    2. Relevant equations
    Period= 2pi/(abs b)


    3. The attempt at a solution
    I found the period as 2pi/(4+pi), this is said to be no the correct answer, how do you simplify this down so it is the exact value???
     
  2. jcsd
  3. Mar 18, 2010 #2

    Mark44

    Staff: Mentor

    6 sin(4x + pi) = 6 sin(4 (x +pi/4))

    What's the period of y = 6 sin(4x)? It's the same as your function. The difference between this function and yours is that one is a horizontal translation of the other.
     
  4. Mar 18, 2010 #3
    Thank you
     
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