Period of a Sine Wave: Understand How to Measure in Radians

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Discussion Overview

The discussion revolves around the concept of measuring the period of sine wave functions in radians, particularly focusing on how the period changes with different angular frequencies. Participants explore the relationship between time, angle, and the definition of period in the context of sine functions.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • Some participants express confusion about how the period of sine functions can be measured in radians, questioning how a full cycle can be anything other than 2π radians.
  • Others propose that the parameter t in sine functions represents time rather than an angle, suggesting that the period can be interpreted in terms of time taken to complete a cycle.
  • There is a discussion about the distinction between measuring periods in radians and measuring distances, with some suggesting that wavelengths might be a more appropriate measure of distance.
  • Participants note that radians are dimensionless and can be used to measure both angles and periods, leading to different interpretations depending on the context.
  • Some participants highlight the difference between the period of a function and the period of the variable, suggesting that the nature of the function influences its periodicity.
  • There is a mention of viewing the measurement of angles and periods from different perspectives, such as considering the scale or the object being measured.

Areas of Agreement / Disagreement

Participants generally express confusion and uncertainty regarding the measurement of periods in radians, with multiple competing views on how to interpret these measurements. The discussion remains unresolved, with no consensus reached on the relationship between period, angle, and time.

Contextual Notes

Participants reference the relationship between angular frequency and period, but there are unresolved assumptions regarding the definitions and implications of measuring periods in radians versus time. The discussion also touches on the nature of independent and dependent variables in relation to periodic functions.

NickTheFill
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Dear all
Something is bugging me. I hope you can help.

I read in texts that if f(t) = sin(t) then the period of the function is the time taken (secs) to complete one cycle.
I also read in texts that if f(t) = sin(2t) then the period of the halved.
No problems here. I see that (2*t) = (omega*t). Happy days.

I also read in texts that if f(x) = sin(x) then the period of the function is 2pi radians.
and that if f(x) = sin(2x) then the period of the function is pi radians.

How can this happen? How can we measure a period in radians? How can a full cycle be anything other than 2pi radians anyway?

I am going round in circles...

Thanks for reading.

Nick
 
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NickTheFill said:
Dear all
Something is bugging me. I hope you can help.

I read in texts that if f(t) = sin(t) then the period of the function is the time taken (secs) to complete one cycle.
I also read in texts that if f(t) = sin(2t) then the period of the halved.
No problems here. I see that (2*t) = (omega*t). Happy days.

I also read in texts that if f(x) = sin(x) then the period of the function is 2pi radians.
and that if f(x) = sin(2x) then the period of the function is pi radians.

How can this happen? How can we measure a period in radians? How can a full cycle be anything other than 2pi radians anyway?
You've already said it: by running through the circle at doubled speed. In this case, the parameter ##t## is simply a measurement of time and not an angle. It is twice the angle so you reach the full circle after ##\pi## units of time. Either you consider the period as purely the distance (measured by whatever unit) between two maximums, or by an angle in which case the factor two has to be part of the drawing. It is basically the standard question with coordinates: does the scale change or the object? One can look at it both ways, but not both at the same time.
I am going round in circles...

Thanks for reading.

Nick
 
Thanks for the swift reply
fresh_42 said:
It is twice the angle so you reach the full circle after ππ\pi units of time.
. My mind looks at this as twice the angular frequency not twice the angle, so the particle completes a full cycle of 2pi radians in half the time. If the period happens to be 2pi seconds then with twice the angular frequency the period is now pi seconds.

It is the reference to measuring periods in radians that i do not understand as a full cycle can only ever be 2pi radians.

If we are talking about measuring a distance, would that not be be wavelengths?
 
NickTheFill said:
Thanks for the swift reply
. My mind looks at this as twice the angular frequency not twice the angle, so the particle completes a full cycle of 2pi radians in half the time. If the period happens to be 2pi seconds then with twice the angular frequency the period is now pi seconds.

It is the reference to measuring periods in radians that i do not understand as a full cycle can only ever be 2pi radians.
You combine two different concepts here: period and angle. Radians are simply a dimensionless quantity, a number. You can use it to measure angles, if a full circle is partitioned in ##2\pi ## steps, or as the period of ##\sin \omega t##, in which case you partitioned named period into only ##\pi## steps, if ##\omega = 2##.
If we are talking about measuring a distance, would that not be be wavelengths?
That's a possibility. But on a circle, this distance will depend on radius (usually ##1##) and angular velocity ##\omega##. Again, it is the concept of measurement you're dealing with: units and coordinates. It's as in the movie: Honey, I shrunk the kids. You can view it as a shrinkage from the point of an unchanged environment or as an enlargement, from the point of the shrunken object. Either way is possible, but not at the same time.

If we say ##\varphi = 2 \pi [\text{radians}]## is the angle of a full circle, then ##\varphi = \pi [\text{radians}_{new}]## is also a full circle, but this time, we measured in ##\text{radians}_{new} = 2\cdot \text{radians}##, and the new radians is not the same angle as the old one. It is a different unit.
 
NickTheFill said:
Thanks for the swift reply
. My mind looks at this as twice the angular frequency not twice the angle, so the particle completes a full cycle of 2pi radians in half the time. If the period happens to be 2pi seconds then with twice the angular frequency the period is now pi seconds.

It is the reference to measuring periods in radians that i do not understand as a full cycle can only ever be 2pi radians.

If we are talking about measuring a distance, would that not be be wavelengths?

There's a difference between the period of a function and the period of the variable. When you talk about the period of a function that is the change in the variable that causes the function values to repeat.
 
If we say ##\varphi = 2 \pi [\text{radians}]## is the angle of a full circle, then ##\varphi = \pi [\text{radians}_{new}]## is also a full circle, but this time, we measured in ##\text{radians}_{new} = 2\cdot \text{radians}##, and the new radians is not the same angle as the old one. It is a different unit.[/QUOTE]

Yes, I think this point is where my confusion lies. A radian is an SI derived unit and I treat it like a kg or a second, it is 57.3 degrees. So to say π radians can be the angle of a full circle is just not cricket!

If we say the x-axis is the angle, then the period of one oscillation of a sine wave is only ever 2π radians and the only distance traveled is an angular distance.

If we say the x-axis is time, then the period of one oscillation can be anything depending on the angular frequency of the oscillation.
 
PeroK said:
There's a difference between the period of a function and the period of the variable. When you talk about the period of a function that is the change in the variable that causes the function values to repeat.
Never thought about the period of a variable. I'm not sure my mind is up to that! I consider an independent variable to be just that and the dependent variable a function of it. It is the nature of the function that causes the periodic nature not the nature of the independent variable.
 

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