Finding the force between 2 finite length wires

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Homework Help Overview

The discussion revolves around calculating the force between two finite length wires carrying a direct current. The wires are specified to be 2 meters long and 3 mm apart, with a current of 10 A flowing through each. Participants are exploring the relevant equations for magnetic fields and forces between current-carrying wires.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of equations for force and magnetic field, considering both finite and infinite wire scenarios. There is an attempt to substitute known values into the equations, and questions are raised about the implications of wire length relative to distance apart.

Discussion Status

The conversation is active, with participants providing guidance on combining equations and correcting errors in calculations. There is an acknowledgment of the need to consider different approaches based on the relative lengths of the wires and their separation.

Contextual Notes

There is a noted discrepancy in the distance between the wires, with one participant correcting the original poster's misunderstanding of the distance as 0.002 m instead of 3 mm. The discussion also hints at the complexity introduced when the wires cannot be considered infinitely long.

jimmyting
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[SOLVED] Finding the force between 2 finite length wires

Homework Statement


The two wires of length 2m are 3mm apart and carry a current of 10 A dc.
calculate the force between these wires.

Homework Equations


Well, I know that the force is found with [tex]F=IL\times B[/tex]
Since we aren't given B, the equation for magnetic field is [tex]B= \frac{\mu\mi_{o}}{4\pi}\frac{IL\times\hat{r}}{r^{2}}[/tex]

A possibly relating equation is the equation for an infinite long wire
[tex]B= \frac{\mu\mi_{o}I}{2\pi r}[/tex]

The Attempt at a Solution


I plugged in what I knew for all the variables, and ended up with an answer of 4.44 repeating
I substituted 10 for I (both times since it is the same current for both wires)
r^ was 1 because the wires are // causing a perpendicular field
L was 2 because it is the length the current traveled in
r was .003 because it is the distance between which the force is being applied.

With those substitutions, what am I doing wrong?
 
Last edited:
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Hi jimmyting,

You'll want to use the first and last equation here. You can actually combine them by inserting the value of B (the last equation) into the first equation for F. The result is a standard textbook equation for the force between two infinitely long, parallel wires:

[tex] \frac{F}{L} = \frac{\mu_0 I_1 I_2}{2 \pi d}[/tex]

This is derived assuming infinitely long wires, but you can apply it here because the wires are so close compared to their length. What do you get for the force?

(Also, in your section 3 you said that r was 0.002, but the problem said they were 3 mm apart.)
 
Wow thank you for catching my error in the last part. It works out, thanks.
But if the segments were close in length comparably to the distance apart, would you need to apply the second equation?
 
Do you mean if the wires could not be considered infinitely long? Then the answer would be yes, you would need to use the differential form:

[tex] dB = \frac{\mu_0}{4\pi} \frac{I d\ell \times \hat r}{r^2}[/tex]

and integrate to find the formula for B for that particular current configuration. (Of course, your textbook should have already done this for some common current configurations and you can just look up the formula for B for those cases.)
 

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