Finding the force (complicated)?

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SUMMARY

The discussion centers on calculating the third force (F3) acting on an object with a mass of 6.70 kg and an acceleration vector of (1.17 m/s²)x + (-0.664 m/s²)y. Given the forces F1 = (2.71 N)x and F2 = (-1.55 N)x + (2.05 N)y, participants emphasize the need to resolve the forces into their x and y components. The net force can be determined using the equation F = ma, where the total force in each direction must be calculated separately to find F3 accurately.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Ability to resolve vectors into components
  • Familiarity with force notation in physics
  • Basic knowledge of gravitational force and its relevance in force calculations
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  • Practice resolving forces into x and y components using vector addition
  • Study examples of multi-force problems in classical mechanics
  • Learn about free-body diagrams to visualize forces acting on an object
  • Explore the implications of gravitational force in various contexts
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Students studying physics, particularly those focusing on mechanics, and anyone looking to enhance their problem-solving skills in force calculations.

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Homework Statement


An object of mass m = 6.70 kg has an acceleration a = (1.17 m/s2)x + (-0.664 m/s2)y. Three forces act on this object: F1, F2, and F3. Given that F1 = (2.71 N)x and F2 = (-1.55 N)x + (2.05 N)y, find F3.
( N)x + ( N)y


Homework Equations



I'll be honest, i have no clue. i know F=ma but have absolutely no clue since there are 3 forces and the x's and y's
 
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you need to break up all the forces into x and y components. (including mg, normal force) find the net force x and y and use F=ma to find the missing x and y, then add these forces together, (its not just x+y) and that it!
 
Yes, add the forces but I see no reason to assume that "surface of the Earth gravitation" should be included. The problem says specifically that there are three forces.
 

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