1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Finding the fourth root of 6.0 x 10

  1. Jun 1, 2010 #1
    1. The problem statement, all variables and given/known data

    If Kp = 6.0 x 108

    For equilibrium N2 <--> 2N

    Then what is the equilibrium constant of

    N <--> .5N2


    2. Relevant equations
    K= C^c/A^a


    3. The attempt at a solution

    I tried finding the fourth root of 6.0 x 108 and that didn't give the right result. BTW the answer is 4.1 x 103, I'm just looking for the way to solve the problem.
     
  2. jcsd
  3. Jun 2, 2010 #2

    Borek

    User Avatar

    Staff: Mentor

    Re: Equilibrium

    Write both reaction quotients, see if you can express one as a function of the other.

    --
    methods
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook