Finding the fourth root of 6.0 x 10

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Homework Statement



If Kp = 6.0 x 108

For equilibrium N2 <--> 2N

Then what is the equilibrium constant of

N <--> .5N2

Homework Equations


K= C^c/A^a

The Attempt at a Solution



I tried finding the fourth root of 6.0 x 108 and that didn't give the right result. BTW the answer is 4.1 x 103, I'm just looking for the way to solve the problem.
 
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Write both reaction quotients, see if you can express one as a function of the other.

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