Finding the frequency of very small oscillations

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SUMMARY

The discussion focuses on calculating the frequency of small oscillations around the equilibrium distance of two particles in a potential well defined by U(r). The equilibrium distance is determined as r_equilibrium = 2^(1/6)*a by setting the derivative of the potential U'(r) to zero. The frequency of oscillations is derived using a Taylor expansion, resulting in k = 9*2^(2/3)*E_0/a^2 and the final expression for angular frequency ω = (3*2^(1/3)/a)*sqrt(E_0/μ).

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  • Understanding of potential wells and equilibrium distances
  • Familiarity with Taylor expansions in physics
  • Knowledge of harmonic motion and angular frequency
  • Basic skills in calculus, particularly differentiation
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  • Learn about harmonic oscillators and their properties
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Students in physics, particularly those studying mechanics and oscillatory motion, as well as educators looking for examples of potential wells and small oscillation analysis.

Bjarni
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Homework Statement
Find the frequency of very small oscillations around the equilibrium distance
Relevant Equations
U(r) = E_0[(a/r)^12- (a/r)^6]
r_equilibrium = 2^(1/6)*a
So I'm working on this home assignment that has numerous segments. Firstly, I was asked to find the equilibrium distance between two particles in a potential well described by U(r).

I did that by setting U'(r) = 0 and came out with r_equilibrium = 2^(1/6)*a.

Now, I'm being asked to find the frequency of very small oscillations around r_equilibrium and I'm honestly lost. I think I only need a small push in the general direction of the solution because as of now I don't really know where to start.

Thanks in advance.
 
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For very small oscillations you can approximate the potential by a parabola.
 
Thanks.

I used a Taylor-expansion and set F = -k(r-r_0) = -dU/dr.

Got k = 9*2^(2/3)*E_0/a^2

and since ω = sqrt(k/μ), I ended up with ω = (3*2^(1/3)/a)*sqrt(E_0/μ) which I feel pretty good about.

Sorry for my lack of LaTex skills..
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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