1. The problem statement, all variables and given/known data Spiderman steps from the top of a tall building. He falls freely from rest to the ground a distance of h. He falls a distance of h/4 in the last interval of time of 1.2 s of his fall. What is the height h of the building? The acceleration is constant -g. 2. Relevant equations y(t) = y(0) + v(0)t - 1/2gt^2 v = v(0) - gt v^2 = v(0)^2 - 2g(y-y(0)) 3. The attempt at a solution I found the average velocity of the final interval of time to be (h/4)m / 1.2s = (h/4.8)m/s. I know the average velocity occurs at half the displacement; so, I used this velocity as the initial velocity for another displacement of h/8 (or half the distance of the final interval). Then I tried using g = -9.8m/s^2, v(0) = -(h/4.8)m/s, y(0) = (h/8)m, and y = 0 to find the time spiderman takes to travel that distance, but I cannot do that without figuring out h, my original target. Please help.