- #1

teatime95

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## Homework Statement

A falling stone takes 0.28 s to travel past a window 2.2 m tall.

From what height above the top of the window did the stone fall?

So from this problem I think I have these variables:

vo = ? (or 0 because falling usually indicates 0 for an initial velocity?)

yo = 0

y = 2.2m

t = 0.28s

a = -9.8m/s^2

## Homework Equations

Kinematic equations:

y=yo+vo*t + 1/2*a*t^2

v^2 = v^20 + 2a(y-y0)

## The Attempt at a Solution

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I originally tried to use the first equation above, and solve for vo if I assumed it was not equal to zero.

So I isolated vo and got,

vo = -2.2 + 1/2(-9.8m/s^2)(0.28s)^2 / -0.28s

vo = 9.229m/s

After which I tried to substitute that value in my second equation which also didn't give me the correct answer for height (which i think is the new yo)

My textbook gives me the final answer but not the steps that it reached to get to it.

I have included the final answer here in white ink (so highlight to read) In case anyone wants to check their work or work backwards: [COLOR=#black]2.1m [/COLOR]

I feel like my process and identifying my variables given correctly is wrong and I'm at that point where I am confusing myself repeating this question.

Guidance would greatly be appreciated,

Thank you all!

Newbie in Physics