Finding the height of an image reflected through a lens?

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The discussion centers on finding the height of an image formed by a lens from a candle flame located 2.1 m from a wall. The lens has a focal length of 37 cm, leading to the conclusion that there are two positions for the lens to create a well-focused image. The user initially struggles with the calculations but realizes that using the lens formula and substituting values can simplify the process. After some reflection, they determine that the heights of the images are approximately 0.65 cm and 6.2 cm, although they express uncertainty about the accuracy of these results. The conversation highlights the importance of understanding the relationships between object distance, image distance, and image height in lens optics.
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Homework Statement



A 2.0--tall candle flame is 2.1 m from a wall. You happen to have a lens with a focal length of 37 cm .

How many places can you put the lens to form a well-focused image of the candle flame on the wall?

For each location, what are the height and orientation of the image?

Homework Equations



1/f=1/s'+1/s

h'=(s'/s)h

The Attempt at a Solution



So I think there are 2 places you can place the lens because s'+s=210cm and s' and s are interchangeable or something like that. I'm not quite sure though.

But then for the second part, i found the heights to be .65 and 6.2 cm but either one or both are wrong. I know I have to find the values for s and s' and I'm not quite sure how to do that. I thought s' would just be 2.1 but how can you have two values for it then?
 
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Put s' = 210 - s and substitute it in the lens formula to find s.
 
ah..just realized that myself.
that's so simple. i was definitely over thinking it.

thanks!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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