Finding the height of an image reflected through a lens?

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SUMMARY

The discussion centers on determining the height and orientation of an image formed by a lens with a focal length of 37 cm, placed to project the image of a 2.0 m tall candle flame located 2.1 m from a wall. The lens formula, 1/f = 1/s' + 1/s, is utilized to find two possible positions for the lens, leading to image heights of 0.65 cm and 6.2 cm. The user initially struggled with the calculations but ultimately recognized the need to substitute s' = 210 - s into the lens formula to solve for s.

PREREQUISITES
  • Understanding of the lens formula (1/f = 1/s' + 1/s)
  • Knowledge of image height calculation (h' = (s'/s)h)
  • Familiarity with focal length concepts in optics
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the principles of geometric optics and lens behavior
  • Learn about the significance of focal length in image formation
  • Explore real-world applications of lenses in photography and vision correction
  • Practice solving lens-related problems using different object distances
USEFUL FOR

Students studying optics, physics enthusiasts, and anyone looking to understand image formation through lenses will benefit from this discussion.

surfahgirl
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Homework Statement



A 2.0--tall candle flame is 2.1 m from a wall. You happen to have a lens with a focal length of 37 cm .

How many places can you put the lens to form a well-focused image of the candle flame on the wall?

For each location, what are the height and orientation of the image?

Homework Equations



1/f=1/s'+1/s

h'=(s'/s)h

The Attempt at a Solution



So I think there are 2 places you can place the lens because s'+s=210cm and s' and s are interchangeable or something like that. I'm not quite sure though.

But then for the second part, i found the heights to be .65 and 6.2 cm but either one or both are wrong. I know I have to find the values for s and s' and I'm not quite sure how to do that. I thought s' would just be 2.1 but how can you have two values for it then?
 
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Put s' = 210 - s and substitute it in the lens formula to find s.
 
ah..just realized that myself.
that's so simple. i was definitely over thinking it.

thanks!
 

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