Finding the Ideal Angle for Maximum Distance with Friction

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SUMMARY

The ideal angle for achieving maximum horizontal distance when throwing an object, without friction, is 45 degrees, as established by the formula s = v²sin(2θ)/g. However, when factoring in friction, the optimal angle decreases slightly below 45 degrees. This adjustment is necessary to account for the energy lost due to frictional forces acting on the object during its flight. Further mathematical proof is required to derive the exact angle considering friction.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with the formula s = v²sin(2θ)/g
  • Basic knowledge of friction and its effects on motion
  • Ability to manipulate trigonometric functions
NEXT STEPS
  • Research the impact of friction on projectile motion
  • Learn how to derive the modified projectile motion equations with friction
  • Explore the concept of optimal launch angles in physics
  • Investigate numerical methods for solving projectile motion problems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for insights into teaching these concepts effectively.

vagelier
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Homework Statement


So for physics, I am trying to establish what the ideal angle is to get a maximum horizontal distance when you throw an object. So far, by using the formula s = v²sin(2θ)/g I've discovered that the angle is 45 degress without friction (duh). But now I need to have a formula to calculate the ideal angle with friction. I know it should be a little below 45 degrees, but I still need to prove it by equation.


Homework Equations


s = v²sin(2θ)/g


The Attempt at a Solution


see 1.
 
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vagelier said:

Homework Statement


So for physics, I am trying to establish what the ideal angle is to get a maximum horizontal distance when you throw an object. So far, by using the formula s = v²sin(2θ)/g I've discovered that the angle is 45 degress without friction (duh). But now I need to have a formula to calculate the ideal angle with friction. I know it should be a little below 45 degrees, but I still need to prove it by equation.


Homework Equations


s = v²sin(2θ)/g


The Attempt at a Solution


see 1.

Why would SIN(28) be a constant?

Also, aiming a cannon lower than 45 degrees produces a greater firing range regardless of frictiion.

Have you left things out?
 

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