Finding the Ideal Angle for Maximum Distance with Friction

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vagelier
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Homework Statement


So for physics, I am trying to establish what the ideal angle is to get a maximum horizontal distance when you throw an object. So far, by using the formula s = v²sin(2θ)/g I've discovered that the angle is 45 degress without friction (duh). But now I need to have a formula to calculate the ideal angle with friction. I know it should be a little below 45 degrees, but I still need to prove it by equation.


Homework Equations


s = v²sin(2θ)/g


The Attempt at a Solution


see 1.
 
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vagelier said:

Homework Statement


So for physics, I am trying to establish what the ideal angle is to get a maximum horizontal distance when you throw an object. So far, by using the formula s = v²sin(2θ)/g I've discovered that the angle is 45 degress without friction (duh). But now I need to have a formula to calculate the ideal angle with friction. I know it should be a little below 45 degrees, but I still need to prove it by equation.


Homework Equations


s = v²sin(2θ)/g


The Attempt at a Solution


see 1.

Why would SIN(28) be a constant?

Also, aiming a cannon lower than 45 degrees produces a greater firing range regardless of frictiion.

Have you left things out?