Finding the initial velocity, .

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Homework Help Overview

The problem involves determining the initial velocity from a given position function of an object over time, expressed as x = 2.257 + 4.894t + 16.5t². Participants are also asked to identify whether the acceleration is constant based on the expression provided.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the given position function and the standard kinematic equation. There is uncertainty about how to correctly identify the initial velocity and acceleration from the equation.

Discussion Status

Some participants have offered guidance on interpreting the components of the equation, while others express confusion about the setup and calculations. Multiple interpretations of the variables are being explored, and there is ongoing dialogue about the correct approach to derive the initial velocity.

Contextual Notes

Participants note that they are working within the constraints of a homework assignment, which may limit the information available for solving the problem. There is also mention of a derivative approach to finding velocity, indicating a potential method under consideration.

megkirch
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Homework Statement


The position x of an object as a function of time is given as x = 2.257 + 4.894 t + 16.5 t2. All quantities are understood to be quoted in SI units. What is the initial velocity ? Indicate with a negative (positive) sign whether the acceleration is constant (not constant) for the given expression.


Homework Equations


i think i have to use. x=x0+v0(t)+1/2(a)t^2)


The Attempt at a Solution


the problem is confusing me becuase I am not sure what numbers should go where in the equation. i know the initial velocity is v0.
 
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So can you compare the equation you wrote in (2) with the one you wrote in (1)?
 
2.257 would be the x0, 4.894 would be the t, and 16.5 would go where the t^2 is. I am not sure what to put as the a.
 
welcome to pf!

hi megkirch! welcome to pf! :wink:
megkirch said:
2.257 would be the x0, 4.894 would be the t

yes :smile:
… , and 16.5 would go where the t^2 is. I am not sure what to put as the a.

16.5 is the ½a :wink:
 
ohh ok thank you! So it would be, x=2.257+V0(4.894)+1/2(16.5)?
 
megkirch said:
ohh ok thank you! So it would be, x=2.257+V0(4.894)+1/2(16.5)?

i hesitate to dampen your enthusiasm, but that doesn't really make any sense :-p

would you like to rephrase it? :smile:
 
do i have that equation set up right?
 
i have been stuck on this one problem all day, please help.
 
What I would do is derive the equation using nx^n-1 where n represents the power in terms of time and you will get the equation that represents velocity.

from this equation, v= v0 + at, what can you say about v0 in the equation that you derived. (hint: the derived equation is identical to the velocity equation)
 
  • #10
megkirch said:
do i have that equation set up right?

the equation is x = 2.257 + 4.894 t + 16.5 t2

you have to find v0 and a …

so what is a?​
 
  • #11
sorry, I am completely lost
 
  • #12
do you know how to find a derivative?
 
  • #13
yes the derivative of the equations is. 2.257=0 4.894t=4.894 16.5t^2=33.
 
  • #14
thank you so much! i finally got the answer its 4.894
 
  • #15
thats what I think :) want a second opinion? I mean I'm sure that's right.
 
  • #16
my homework is online it said its right. thank you again
 

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