Finding the Limit of a Root Test: Calculating the Limit of a Challenging Term

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Homework Help Overview

The discussion revolves around finding the limit of a term involving a root test, specifically the expression $$\lim_{{n}\to{\infty}}|\left(\frac{n}{n+1}\right)^{\!{n^2}}|^\frac{1}{n}$$. Participants are exploring the steps involved in simplifying this limit and understanding the transitions between different forms of the expression.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand the manipulation of the limit expression, particularly how the denominator changes when rewriting the term. Questions arise regarding the implications of dividing terms by n and the resulting effects on the limit.

Discussion Status

The discussion is active, with participants clarifying each other's points and addressing typographical errors. There is an ongoing exploration of the mathematical reasoning behind the steps taken in the limit calculation, but no consensus has been reached on the specific confusion regarding the third line of the original poster's working.

Contextual Notes

Participants are navigating through potential misunderstandings related to the algebraic manipulation of limits and the properties of exponents. The original poster's working includes a step that raises questions about the treatment of terms as n approaches infinity.

MissP.25_5
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Hello.
How do I find the limit of this term?

$$\lim_{{n}\to{\infty}}|\left(\frac{n}{n+1}\right)^{\!{n^2}}|^\frac{1}{n}$$

This is the working but I don't understand how to get the third line.

r = lim(n→∞) |[n/(n+1)]^(n^2)|^(1/n)
..= lim(n→∞) [n/(n+1)]^n
..= lim(n→∞) 1 / [(n+1)/n]^n
..= lim(n→∞) 1 / (1 + 1/n)^n
..= 1/e, by the limit definition of e.
 
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##\frac 1{\frac{n+1}n}=\frac n{n+1}## and ##(\frac 1a)^n = \frac 1{a^n}##, right?
 
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Erland said:
##\frac 1{\frac{n+1}n}=\frac n{n+1}## and ##(\frac 1a)^n = \frac 1a^n##, right?

Yes, but as you can see, the third line has its denominator to the power of n. That's what I don't understand. If we divide all terms with n, then what happens to the n outside the bracket?
 
Sorry, there was a typo in my reply which I corrected immediatly, but you were so quick and got the typo in your reply...
 
Erland said:
Sorry, there was a typo in my reply which I corrected immediatly, but you were so quick and got the typo in your reply...

Yeah, I was quick, haha. As soon as I submitted my post, I saw you have corrected your error. Thank you!
 

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