Finding the Limit of a Strange Sequence: How to Use Stirling's Approximation

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SUMMARY

The limit of the sequence \([(1+1/n)(1+2/n)(1+3/n)...(1+n/n)]^{(1/n)}\) as \(n\) approaches infinity is definitively \(4/e\). The sequence can be transformed into \([(2n)!/(n!*n^n)]^{(1/n)}\), which simplifies the analysis. Applying Stirling's approximation, specifically \(n! \sim \sqrt{2\pi n} (n/e)^n\), provides the necessary framework to evaluate the limit effectively.

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  • Understanding of limits in calculus
  • Familiarity with Stirling's approximation
  • Knowledge of factorial functions
  • Basic algebraic manipulation skills
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  • Study Stirling's approximation in detail
  • Explore the properties of limits and convergence
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Students studying calculus, mathematicians interested in sequences, and anyone looking to deepen their understanding of Stirling's approximation and its applications in limit evaluation.

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Homework Statement



I need to find the limit of the sequence:

[(1+1/n)(1+2/n)(1+3/n)...(1+n/n)]^(1/n) as n approaches infinity.

I know that the limit should come out to 4/e, but I cannot figure out why.

Homework Equations



None.

The Attempt at a Solution



The original sequence is equivalent to [(2n)!/(n!*n^n)]^(1/n), but I have absolutely no idea what to do with it after that. Can anybody point me in the right direction?
 
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Why not just apply Stirling's approximation to the original sequence?
 

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