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Finding the magnitude and direction of current thro Kirchhoff law

  1. Dec 28, 2012 #1
    1. The problem statement, all variables and given/known data

    Revered Members,
    Please go through my attachment. I have been asked to find the magnitude and direction of current through the 10 ohm resistor. The answer that is given in the book is 1/23 Ampere from A to B.
    But i solved as given in the attachment but i got the answer as 5/37 Ampere which is I3...the current which I assumed to pass through 10 ohm resistor. Since Please help me where i went wrong.

    2. Relevant equations



    3. The attempt at a solution
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     

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  2. jcsd
  3. Dec 28, 2012 #2

    gneill

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    Staff: Mentor

    Your work and results look fine. Must be an error in the book's answer.
     
  4. Dec 28, 2012 #3

    rude man

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    Homework Helper
    Gold Member

    I used the superposition principle as follows:

    1. Short the 2V source & get voltage across the 10Ω = +2.1622V.
    2. Short the 8V source and get same voltage = -0.8108V
    3. Superpose the voltages to get +1.3514V across the 10Ω.
    4. Divide by 10Ω to get i3 = 0.13514A which agrees with both of you!
     
  5. Dec 30, 2012 #4
    Thank you gneill and rude man for your help.
     
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