- #1

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- Homework Statement
- See image attached

- Relevant Equations
- Kirchhoff's 1st and 2nd law

Struggling to see if I am doing this right or not from a section of a question I have been given

I have drawn out a sketch of the circuit again, and labelled as to what my 1st and 2nd closed loop to be to then apply Kirchhoff's 2nd law

I get a negative I_2 current which just indicates that my original assumption of the currents direction was wrong and it is in fact going the opposite way

So I believe that the current going through:

6 ohm resistor = 0.703 A

1 ohm resistor = 1.162 A

4 ohm resistor = 0.459 A

Is this right or have I miserably gone wrong somewhere?

Any help would be really appreciated! Thanks

I have drawn out a sketch of the circuit again, and labelled as to what my 1st and 2nd closed loop to be to then apply Kirchhoff's 2nd law

I get a negative I_2 current which just indicates that my original assumption of the currents direction was wrong and it is in fact going the opposite way

So I believe that the current going through:

6 ohm resistor = 0.703 A

1 ohm resistor = 1.162 A

4 ohm resistor = 0.459 A

Is this right or have I miserably gone wrong somewhere?

Any help would be really appreciated! Thanks

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