Finding the maximum height of a rocket

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The discussion focuses on calculating the maximum height of a rocket that accelerates upward with a constant net acceleration until its fuel is exhausted. The correct formula for maximum height, considering both the upward acceleration and the effect of gravity, is expressed as (at)^2/2g + 1/2at^2. This equation accounts for the initial velocity of the rocket and the gravitational pull acting on it after the fuel runs out. Participants clarify that the rocket's trajectory is parabolic, meaning it continues to rise briefly after fuel depletion before descending. The conversation emphasizes the importance of including both acceleration and gravity in the height calculation.
hieule
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A rocket, initially at rest on the ground, accelerates straight upward from rest with constant net acceleration a, until time t_1, when the fuel is exhausted.

Find the maximum height H that the rocket reaches (neglecting air resistance).
Express the maximum height in terms of a, t_1, and/or g. Note that in this problem, g is a positive number equal to the magnitude of the acceleration due to gravity.

my answer is:
(at)^2/2g +1/2at^2

is that correct yet?
 
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hieule said:
A rocket, initially at rest on the ground, accelerates straight upward from rest with constant net acceleration a, until time t_1, when the fuel is exhausted.

Find the maximum height H that the rocket reaches (neglecting air resistance).
Express the maximum height in terms of a, t_1, and/or g. Note that in this problem, g is a positive number equal to the magnitude of the acceleration due to gravity.

my answer is:
(1/2)*(g)*(t1)^2

but that is incorrect

Your equation only shows the distance as far as when the fuel is gone. A rocket's path is a parabola.. when it shoots up and then runs out of fuel, it will go up a little more and then start to fall.
 


Yes, your answer is correct. The maximum height reached by the rocket can be expressed as (at)^2/2g +1/2at^2, where a is the constant acceleration, t is the time at which the fuel is exhausted, and g is the acceleration due to gravity. This formula takes into account the initial velocity of the rocket (which is zero) and the fact that the rocket is accelerating both due to its own engine and the force of gravity.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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