Finding the Minimum Coefficient of Friction Equation

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Homework Help Overview

The discussion revolves around identifying the correct equation for the minimum coefficient of friction, particularly in the context of motion, possibly involving circular motion or inclined planes. Participants are exploring the relationship between forces and the coefficient of friction.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are questioning the validity of two proposed equations for the minimum coefficient of friction and examining their units. There is a focus on understanding the nature of the coefficient of friction and its unitless characteristic.

Discussion Status

The discussion is active, with participants providing insights into the units of the proposed equations and questioning the assumptions behind the definitions of the coefficient of friction. Some guidance has been offered regarding the need to analyze units, but no consensus on the correct equation has been reached.

Contextual Notes

Participants mention the need for context in understanding the minimum coefficient of friction, suggesting that it may depend on specific conditions such as preventing sliding on an incline or maintaining circular motion.

BigMann
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stupid question because I forgot the equation

What is the equation for the minimum value of the coefficient of friction?

is it m(v^2/r) or v^2/gr
 
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check your units on them -- think about the units of the coefficient of friction -- then does one or the other make sense?
 
the correct equation is v^2/gr right?
 
well -- what are the units of that, and what are the units of the coefficient of friction?
 
I know that the coefficient of friction is Newtons
 
BigMann said:
I know that the coefficient of friction is Newtons
It's what we "know" that hurts! The Newton is a unit of force. While friction is a force, the coefficient of friction is not.
 
This then means that the first equation would have to be the right one based off of the units. And if I am incorrect than I guess I just forgot it all
 
The units of the first are mass x velocity^2/length -- kg/m^2/s^2/m -- is that the same as the units of the coefficient of friction?

Then analyze the second in the same way.

Analyzing units always helps -- but of course doesn't guarantee the right answer.
 
  • #10
maybe I'm not understanding the units of the coefficient of friction. Could you explain to me what they are?
 
  • #11
BigMann said:
maybe I'm not understanding the units of the coefficient of friction. Could you explain to me what they are?
The coefficient of friction is the ratio of two forces, the force of friction divided by the normal force. It has no units; it is a pure number.

As for your original question
BigMann said:
stupid question because I forgot the equation

What is the equation for the minimum value of the coefficient of friction?

is it m(v^2/r) or v^2/gr
This does not mean much out of context. By minimum value of the coefficient of friction I assume you mean the minimum value required to achieve some condition, such as the minimum value required to keep a block from sliding down an inclined plane or to keep a car going around a curve from skidding. There is no single equation for this. It comes from figuring out how much frictional force is required to acomplish something and dividing that required force by the normal force in the problem.
 

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