Finding the Minimum Velocity for Sustaining Flight Using Dimensional Analysis

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SUMMARY

The minimum velocity required for an object to sustain flight is determined by the relationship between its mass (M), lift force (Fl), and drag force (Fd). Through dimensional analysis, it is established that the scaling factor for minimum velocity is vl(min) ∝ √M, leading to the conclusion that k = 1/2. This indicates that if the mass is doubled, the velocity must increase by a factor of √2, assuming constant density and proportional changes in wing surface area (W) and cross-sectional area (A).

PREREQUISITES
  • Understanding of dimensional analysis in physics
  • Familiarity with lift and drag forces in aerodynamics
  • Knowledge of scaling laws and their applications
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the principles of lift and drag forces in more detail
  • Explore dimensional analysis applications in fluid dynamics
  • Learn about the effects of changing wing surface area on flight dynamics
  • Investigate the relationship between mass, density, and velocity in flight mechanics
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Aerospace engineers, physics students, and anyone interested in the mechanics of flight and aerodynamics will benefit from this discussion.

Beer-monster
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Homework Statement



An flying object of mass M experiences a lift force and a drag force dependent on the it's velocity:

[tex]F_{l} \propto Wv^{2}[/tex]
[tex]F_{d} \propto Av^{2}[/tex]

Where W and A are wing surface area and "cross-sectional" area.

To sustain flight the object must fly at a minimum velocity which scales as [itex]M^{k}[/itex] where k is a constant.

What is k?

Homework Equations



For the object to remain in flight it must produce a lift force equal or greater than it's weight i.e.

[tex]Mg = F_{l(min)} \propto Wv^{2}[/tex]

The Attempt at a Solution

I have found an answer but I'm not too happy with how I got there. Basically, I subbed the scaling factor for minimum velocity into the above equation:

[tex]Mg \propto W(M^{k})^{2} \propto WM^{2k}[/tex]

As the left side only has mass to the power 1 and the right has mass to the power 2k we can get:

[tex]2k=1[/tex]

So k = 1/2 or [itex]v_{l(min)} \propto \sqrt{M}[/itex].

This results makes some sense to me physically, but I'm not happy with my approach as it seems a bit simplistic.
 
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Beer-monster said:

Homework Statement



An flying object of mass M experiences a lift force and a drag force dependent on the it's velocity:

[tex]F_{l} \propto Wv^{2}[/tex]
[tex]F_{d} \propto Av^{2}[/tex]

Where W and A are wing surface area and "cross-sectional" area.

To sustain flight the object must fly at a minimum velocity which scales as [itex]M^{k}[/itex] where k is a constant.

What is k?

Homework Equations



For the object to remain in flight it must produce a lift force equal or greater than it's weight i.e.

[tex]Mg = F_{l(min)} \propto Wv^{2}[/tex]



The Attempt at a Solution




I have found an answer but I'm not too happy with how I got there. Basically, I subbed the scaling factor for minimum velocity into the above equation:

[tex]Mg \propto W(M^{k})^{2} \propto WM^{2k}[/tex]

As the left side only has mass to the power 1 and the right has mass to the power 2k we can get:

[tex]2k=1[/tex]

So k = 1/2 or [itex]v_{l(min)} \propto \sqrt{M}[/itex].

This results makes some sense to me physically, but I'm not happy with my approach as it seems a bit simplistic.

Seems fine to me. If you increase the mass by a factor of ##2## you need to increase the velocity by a factor of ##\sqrt{2}##, all else being fixed. What seems simplistic about it to you?
 
Maybe you are supposed to assume that the object is to be scaled linearly at constant density. Thus W and A will also change.
 

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