Finding the Minimum Velocity for Sustaining Flight Using Dimensional Analysis

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Beer-monster
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Homework Statement



An flying object of mass M experiences a lift force and a drag force dependent on the it's velocity:

[tex]F_{l} \propto Wv^{2}[/tex]
[tex]F_{d} \propto Av^{2}[/tex]

Where W and A are wing surface area and "cross-sectional" area.

To sustain flight the object must fly at a minimum velocity which scales as [itex]M^{k}[/itex] where k is a constant.

What is k?

Homework Equations



For the object to remain in flight it must produce a lift force equal or greater than it's weight i.e.

[tex]Mg = F_{l(min)} \propto Wv^{2}[/tex]

The Attempt at a Solution

I have found an answer but I'm not too happy with how I got there. Basically, I subbed the scaling factor for minimum velocity into the above equation:

[tex]Mg \propto W(M^{k})^{2} \propto WM^{2k}[/tex]

As the left side only has mass to the power 1 and the right has mass to the power 2k we can get:

[tex]2k=1[/tex]

So k = 1/2 or [itex]v_{l(min)} \propto \sqrt{M}[/itex].

This results makes some sense to me physically, but I'm not happy with my approach as it seems a bit simplistic.
 
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Beer-monster said:

Homework Statement



An flying object of mass M experiences a lift force and a drag force dependent on the it's velocity:

[tex]F_{l} \propto Wv^{2}[/tex]
[tex]F_{d} \propto Av^{2}[/tex]

Where W and A are wing surface area and "cross-sectional" area.

To sustain flight the object must fly at a minimum velocity which scales as [itex]M^{k}[/itex] where k is a constant.

What is k?

Homework Equations



For the object to remain in flight it must produce a lift force equal or greater than it's weight i.e.

[tex]Mg = F_{l(min)} \propto Wv^{2}[/tex]



The Attempt at a Solution




I have found an answer but I'm not too happy with how I got there. Basically, I subbed the scaling factor for minimum velocity into the above equation:

[tex]Mg \propto W(M^{k})^{2} \propto WM^{2k}[/tex]

As the left side only has mass to the power 1 and the right has mass to the power 2k we can get:

[tex]2k=1[/tex]

So k = 1/2 or [itex]v_{l(min)} \propto \sqrt{M}[/itex].

This results makes some sense to me physically, but I'm not happy with my approach as it seems a bit simplistic.

Seems fine to me. If you increase the mass by a factor of ##2## you need to increase the velocity by a factor of ##\sqrt{2}##, all else being fixed. What seems simplistic about it to you?