Finding the moment of inertia for a hollow cylinder

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SUMMARY

The moment of inertia for a hollow cylinder with a closed bottom can be calculated by summing the moments of inertia of both the cylinder and the disk at the bottom. The integral formula I = ∫ r² dm is essential for this calculation. To find the mass of each part, one can compare their relative areas, given that the thickness is uniform. The surface area of the cylinder is L x 2πr, while the area of the bottom is πr².

PREREQUISITES
  • Understanding of moment of inertia concepts
  • Familiarity with integral calculus
  • Knowledge of geometric properties of cylinders
  • Basic principles of mass distribution
NEXT STEPS
  • Study the derivation of the moment of inertia for various shapes
  • Learn about uniform mass distribution in solid objects
  • Explore applications of integral calculus in physics
  • Investigate the properties of hollow cylinders in engineering contexts
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Physics students, mechanical engineers, and anyone involved in structural analysis or materials science will benefit from this discussion.

Antares
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I need help finding the moment of inertia for a hollow cylinder with a closed bottom (like a glass of water). My strategy is to add the moments of inertia of the cylinder and the disk but I only have the total mass of the whole object. Is there a way to find the mass of each part or is there another approach to this problem?
 
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Just sum the mass as an integral as follows.

I=\int r^2 dm
 
Antares said:
Is there a way to find the mass of each part or is there another approach to this problem?
If the thickness is uniform then you can find the masses of the cylinder and bottom by comparing their relative areas. The surface area of the cylinder is Lx2πr; the area of the bottom is πr2.
 

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