Finding the moment of inertia of a compound object

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Homework Help Overview

The problem involves calculating the moment of inertia of a compound object consisting of a uniform bar with two point masses attached at its ends. The bar's dimensions and mass are specified, along with the masses of the balls. The discussion focuses on finding the moment of inertia about an axis perpendicular to the bar through its center.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the appropriate equations for calculating the moment of inertia for both the bar and the attached masses. There is a question regarding the addition of the results from different components and the correct application of formulas based on the axis of rotation.

Discussion Status

Some participants have provided guidance on the correct formulas to use for the moment of inertia, while others have clarified the conditions under which these formulas apply. There is an acknowledgment of a misunderstanding regarding the calculations, leading to a resolution for one participant.

Contextual Notes

There is a mention of differing equations for the moment of inertia based on the axis of rotation, highlighting the importance of correctly identifying the axis in relation to the bar's geometry.

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Homework Statement


A uniform bas has two small balls glued to its end, the bar is 2.00 m long, and it has a mass 4.00 Kg, while the balls, have mass 0.500Kg and can be treated as point masses. Find the moment of inertia of this combination about each of the following axes. a) an axis perpendicular to the bar through its center.


Homework Equations


I=1/3ML^2
I=[tex]\Sigma[/tex]mr^2

The Attempt at a Solution


I=1/3ML^2
I=1/3(4.00Kg)(2.00m)^2
I=5.33 Kgm^2

I=[tex]\Sigma[/tex]mr^2
I=(0.500Kg)(2.00m)^2(2)
I=1.0Kgm^2

I tot =6.33 Kgm^2
I am supposed to add both results?, how is the result of hit sexercise 2.33 Kgm^2?
thanks.
 
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I of bar is 1/12*M*L^2.
 
I believe that's the equation when the axis of rotation goes through one of the bar's end. when the axis crosses the center of the bar I=1/3ML^2 according to my textbook.
 
you were right, I am so sorry. thanks. I finally got it.!
 

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