Your moving company runs out of rope and hand trucks, so you are forced to push two crates along the floor. The crates are moveing at constant velocity, their masses are m1=45kg and m2=22kg, and the coefficient of kinetic friction between both crates and the floor are 0.35. Find the normal force between the 2 crates.
Ffriction=coefficient of friction*normal force
The Attempt at a Solution
I know the answer is 75N. I attempted to solve the forces acting on each individual crate then combined the results. I got way to large of an answer. I don't know how to go about solving this another way.