Finding the normalization constant for a 1-D time independent wave function

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SUMMARY

The discussion focuses on finding the normalization constant A for the wave function ψ(x) = A((2kx) - (kx)^2) defined in the interval 0 ≤ x ≤ 2/k. The key equation used is ∫|ψ(x)|^2 dx = 1, which requires squaring the entire wave function, including the constant A, to ensure proper normalization. The solution involves evaluating the integral between the specified limits to determine the value of A.

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Homework Statement



ψ(x)=A((2kx)-(kx)^2)
0≤X≤2/k
ψ(x)=0 everywhere else

I need to find A

Homework Equations



∫|ψ(x)|^2 dx=1

so I know I need to evaluate it between 0 and 2/k

The Attempt at a Solution



My problem is do I square the whole ψ(x)? If some one could point me in right direction I would really appreciate it.
 
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Hello and welcome.

Yes, as long as ψ(x) is a real valued function, then |ψ(x)|2 is just the square of ψ(x) (including the constant A).
 

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