Wave packet width given a wave function

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SUMMARY

The discussion centers on determining the wave packet Ψ(x, t) given the wave function φ(k) defined as A for k0 − ∆k ≤ k ≤ k0 + ∆k and 0 elsewhere. The dispersion relation is specified as ω = vk, where v is a constant. The integral form of Ψ(x, t) is provided, but participants express confusion regarding the significance of the integral and the concept of wave packet width. The need for an analytical form of Ψ is emphasized, indicating that deriving the wave equation from the dispersion relation may be necessary.

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  • Familiarity with Fourier transforms and their application in wave analysis
  • Knowledge of dispersion relations, specifically ω = vk
  • Ability to perform integrals involving complex exponentials
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Homework Statement


Find the wave packet Ψ(x, t) if φ(k) = A for k0 − ∆k ≤ k ≤ k0 + ∆k and φ(k) = 0 for all other k. The system’s dispersion relation is ω = vk, where v is a constant. What is the wave packet’s width?

Homework Equations


[/B]
I solved for Ψ(x, t):

$$\Psi(x,t) = \frac{1}{\pi\sqrt{K_0+\Delta K}} \int_{-\infty}^{\infty} \frac{sin(k(k_0 + \Delta K))}{k} e^{i(kx-hk^2/2m)t}dk$$

The Attempt at a Solution



How would I go about finding the wave packet's width. I'm not even sure what this means. Thank you for any guidance.
 
Last edited:
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I don't understand why you have an integral there. You should be able to find an analytical form for Ψ.
 
DrClaude said:
I don't understand why you have an integral there. You should be able to find an analytical form for Ψ.

Am I supposed to be deriving the the wave equation from the dispersion equation?
 

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