If the wave function is normalized, what is the probability density at x?

  • Thread starter hidemi
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  • #1
hidemi
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Homework Statement:
How to know the answer is D``?
Relevant Equations:
non
The wave function ψ(x) of a particle confined to 0 ≤ x ≤ L is given by ψ(x) = Ax, ψ(x) = 0 for x < 0 and x > L. When the wave function is normalized, the probability density at coordinate x has the value?

(A) 2x/L^2. (B) 2x^2 / L^2. (C) 2x^2 /L^3. (D) 3x^2 / L^3. (E) 3x^3 / L^3

Ans : D
 

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  • #2
BvU
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Is there a question here ?
 
  • #3
BvU
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I see you are pretty new here, so
:welcome: !​

And the PF guidelines ask that you post your own attempt at solution. What did you find ?
 
  • #4
BvU
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Homework Statement:: How to know the answer is D``?
Relevant Equations:: non

The wave function ψ(x) of a particle confined to 0 ≤ x ≤ L is given by ψ(x) = Ax, ψ(x) = 0 for x < 0 and x > L. When the wave function is normalized, the probability density at coordinate x has the value?

(A) 2x/L^2. (B) 2x^2 / L^2. (C) 2x^2 /L^3. (D) 3x^2 / L^3. (E) 3x^3 / L^3

Ans : D
Let me help some more: the homework statement is the part in italics.
Your question (which I missed :rolleyes: ) is the part in red

And the answer follows from calculating A and then the probability density. For that you need the relevant equations. 'non' doesn't do it.

Hint: do the normalizatiion.

##\ ##
 
  • #5
hidemi
208
36
I see you are pretty new here, so
:welcome: !​

And the PF guidelines ask that you post your own attempt at solution. What did you find ?
I think I got it, thanks!
 

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