Finding the number of revolutions for an car in an angular system

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SUMMARY

The discussion focuses on calculating the angular acceleration and the number of revolutions made by an automobile engine as its speed increases from 1500 rev/min to 3900 rev/min over a period of 14 seconds. The angular acceleration was correctly calculated as 10285.71429 rev/min² using the formula α = Δω / time. However, the user expressed uncertainty about calculating the total number of revolutions during the interval, indicating a need for further guidance on the appropriate formulas or methods to use for this calculation.

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Homework Statement



The angular speed of an automobile engine is increased at a constant rate from 1500 rev/min to 3900 rev/min in 14 s.
(A) What is its angular acceleration in revolutions per minute-squared?

(B) How many revolutions does the engine make during this 14 s interval?

Homework Equations


I found out (A) to be 10285.71429 rev/min^2, but I have no idea how to do (B). would have to find tangential velocity or do i have enough information already?

The Attempt at a Solution


for (A), i used the formula [tex]\alpha[/tex] = [tex]\Delta[/tex][tex]\omega[/tex] / time
so (3900rev/min - 1500rev/min)/14,
and this was 10285.71420rev/min^2
i just don't know how to start (B)..
 
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oh sorry, the alpha stands for angular acceleration
the delta of little omega stands for change in anuglar speed :]
 
whoops, change in angular* speed
 

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