Finding the Open Circuit Voltage

AI Thread Summary
The discussion focuses on calculating the open circuit voltage between points XY after the connection is removed while KLM points remain connected. Participants express difficulty in solving the problem and seek guidance on how to approach it. Key equations mentioned include V=IR and Kirchhoff's Voltage Law (KVL). Clarifications are provided regarding the potential at points X and Y, emphasizing the importance of understanding current flow and potential definitions. The conversation highlights the need for accurate calculations and understanding of circuit principles to determine the potential difference.
JamesBennettBeta
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Homework Statement
While KLM points remain connected, the connection between points XY is removed. Calculate the potential difference between points XY in this situation.
Relevant Equations
V=IR, KVL
Problem Statement: While KLM points remain connected, the connection between points XY is removed. Calculate the potential difference between points XY in this situation.
Relevant Equations: V=IR, KVL

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And you will now show us your work...
 
berkeman said:
And you will now show us your work...
I couldn't solve it.
 
JamesBennettBeta said:
I couldn't solve it.
So show us what you tried. We can use that to help guide your approach better. We do not do your work for you here.
 
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Likes DaveE
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Here is how I tried. I don't know how to solve further. I don't know how to calculate the potential difference between those points.

I'm sorry for not understanding how things work here.
New Doc 2019-08-05 20.18.47_1.jpg


I don't know how to find the potential difference between those points. So I can't slove further.

I'm sorry for not understanding how things work here.
 
Since you defined ABC as 0 potential, what is the potential at point Y? Recall that you said there is no current through R3.
Using similar reasoning can you find the potential at point X? What do you need to know to calculate the potential at point X?

Note: your current calculation is off by 1,000,000 times. Except for the sign error it's correct.
 
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