Finding the optical power of a contact lens

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SUMMARY

The discussion focuses on calculating the optical power of contact lenses for a farsighted individual who currently uses eyeglasses with a refractive power of 2.05 diopters. The individual reads at a distance of 0.265 m, with the glasses positioned 0.020 m from the eyes. The solution involves using the lens formula 1/do + 1/di = 1/f, resulting in a contact lens prescription of +1.38 diopters after adjusting for the distance change when switching from glasses to contacts.

PREREQUISITES
  • Understanding of lens formulas, specifically 1/do + 1/di = 1/f
  • Knowledge of diopters as a unit of measurement for lens power
  • Familiarity with the concepts of object distance (do) and image distance (di)
  • Basic principles of optics related to convex lenses
NEXT STEPS
  • Research the effects of lens distance on optical power calculations
  • Learn about the different types of contact lenses and their prescriptions
  • Study the relationship between object distance and image distance in optical systems
  • Explore advanced lens design techniques for correcting vision
USEFUL FOR

This discussion is beneficial for optometry students, optical technicians, and anyone involved in the prescription of corrective lenses, particularly those transitioning from eyeglasses to contact lenses.

ilovejava
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Homework Statement


A farsighted man uses eyeglasses with a refractive power of 2.05 diopters. Wearing the glasses 0.020 m from his eyes, he is able to read books held no closer than 0.265 m from his eyes. He would like a prescription for contact lenses to serve the same purpose. What is the correct contact lens prescription, in diopters?

Homework Equations


1/do+1/di=1/f

The Attempt at a Solution


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The image formed when wearing eyeglasses is 0.265-0.020 = 0.245 and this has to be negative because the man is using convex lenses, so d/i = -0.245 with eyeglasses. Next, I found the the object distance when wearing eyeglasses by using the formula 1/do+1/di=1/f and it turned out to be 0.163 the fact that it's positive makes sense because the object is placed in front of the lens. Now because the questions asks to find the power of the contact lenses the distance of the object when using contacts increases by 0.020m so do with lenses equals 0.183m. Finally I plugged everything into 1/do+1/di=1/f and got +1.38 diopters.
 
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The 0.265 m distance is to the book, which is the object, not the image (for the glasses anyway)!
So what you are calculating for the glasses is the image distance produced by the glasses, which I get a different answer for, so please show your steps to that value so that we are on the same page.
 

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