Geometric Optics and Lens Power

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Homework Help Overview

The discussion revolves around a problem in geometric optics concerning the power of corrective lenses needed for a farsighted individual. The original poster is attempting to determine the appropriate lens power that allows the near point to be no further than 25 cm, given their current near point of 2.3 m.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are discussing the calculation of lens power using the lens formula and questioning the validity of the original poster's calculated value of 3.57 diopters, noting that it does not correspond to available lens increments.

Discussion Status

There is an ongoing exploration of the relationship between the calculated lens power and the available increments of 0.25 diopters. Participants are considering which of the available lens powers (3.5 or 3.75 diopters) would meet the requirement for the near point.

Contextual Notes

Participants are operating under the constraint that corrective lenses are only available in specific increments, which influences the choice of lens power. The original poster's calculation is noted to be outside these increments, prompting further discussion on how to approach the problem.

CCR5
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Homework Statement


A farsighted boy has a near point at 2.3 m and requires eyeglasses to correct his vision.

Corrective lenses are available in increments in power of 0.25 diopters. The eyeglasses

should have lenses of the lowest power for which the near point is no further than 25

cm. The correct choice of lens power for eyeglasses, in diopters, is:

Homework Equations


1/s + 1/s' = 1/f
1/f = P

The Attempt at a Solution


I keep getting a value of 3.57 diopters, however, the correct answer is 3.75.
 
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CCR5 said:
Corrective lenses are available in increments in power of 0.25 diopters.
3.57 diopters does not exist as a choice. :rolleyes:
 
kuruman said:
3.57 diopters does not exist as a choice. :rolleyes:
Wonderful... Can you shed some light on the increment and its relation to the correct answer of 3.75?
 
CCR5 said:
Can you shed some light on the increment ...
You already answered this by yourself!
CCR5 said:
Corrective lenses are available in increments in power of 0.25 diopters.
... and its relation to the correct answer of 3.75
Ergo: you have to chose between 3.5 and 3.75. Now you have to calculate which distance at diopters of 3.5 or 3.75 fulfills the requirement "near point no further than ..."
 
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fresh_42 said:
You already answered this by yourself!Ergo: you have to chose between 3.5 and 3.75. Now you have to calculate which distance at diopters of 3.5 or 3.75 fulfills the requirement "near point no further than ..."

Errm. So based off the given answers, which ever is closest to to my value an estimated value of 0.25 increment? Gotcha! Thank you for your response.
 

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