Finding the period of an object moving in horizontal circle

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The discussion focuses on calculating the speed and period of an object moving in a horizontal circle while suspended by a string. The correct velocity formula is debated, with one participant asserting it should be √(g*L*Cos(θ)) / tan(θ). Clarification is sought on the equivalence of this formula to the derived answer, which is confirmed to be correct if tan(θ) is properly included in the square root. The conversation emphasizes the importance of understanding trigonometric relationships in the context of circular motion. Overall, the discussion highlights the complexities of deriving motion equations in physics.
fontseeker

Homework Statement


A small mass m is suspended from a string of length L. The body revolves in a horizontal circle of radius R with a constant speed v. Find the speed of the body and the period of the revolution.

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Homework Equations



ΣFx = Tx = mV^2/r
Period = (2πr)/V

The Attempt at a Solution



IMG_4437.jpg


However, I was told that the velocity is actually √(g*L*Cos(θ)) / tan(θ). Why is my answer incorrect?
 
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fontseeker said:
However, I was told that the velocity is actually √(g*L*Cos(θ)) / tan(θ). Why is my answer incorrect?
Your answer looks correct. If ##\text{tan}(\theta)## is inside the square root, which I assume it should be, then the given answer is identical to yours.
 
NFuller said:
Your answer looks correct. If ##\text{tan}(\theta)## is inside the square root, which I assume it should be, then the given answer is identical to yours.
Could you please explain how the answer is identical?
 
Tan = sin/cos
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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