**1. Homework Statement**

Two wires are used to connect a lamp to a power supply of negligible internal resistance. The potential difference across the lamp is 12V and its power is 36W. Calculate the potential difference across each wire. The two wires in question are made of copper and have a resistivity of 1.7 x 10^-8 Ohm meter.

**2. Homework Equations**

Not 100% sure but:

V=W/Q, R=V/I, I=P/V, E= I (R + r)

And I'm not sure about an others.

**3. The Attempt at a Solution**

I = 36/12, I = 3

R = 12/3, R = 4

E = 3 (4 + 1.7x10^-8) = 12V

Therefore the potential difference across each wire is 12V

I know I've gone wrong some where and am hoping someone can put me right.

Many thanks,

Sam

**1. Homework Statement**

**2. Homework Equations**

**3. The Attempt at a Solution**