Finding the probability of energy measurements

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SUMMARY

The discussion revolves around calculating the probabilities of energy measurements for a quantum system described by the normalized state \(\phi(t = 0) = \frac{1}{\sqrt{5}}(i\psi_{210} + 2\psi_{211})\). The relevant energy states are derived from the Hamiltonian matrix \(H\), which includes eigenstates \(\psi_{210}\), \(\psi_{211}\), and \(\psi_{21-1}\). The probabilities for measuring these states are calculated using the formula \(P(j) = \left|\langle\psi_j|\Psi\rangle\right|^2\), resulting in \(P(E_{2} + 2\gamma\hbar^{2}) = \frac{1}{5}\) and \(P(E_{2}) = \frac{4}{5}\).

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Denver Dang
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Homework Statement


Hi... My problem says:

In a given experiment the system, at the time [itex]t = 0[/itex], in the normalized state is given by:

[tex]\phi(t =0) = \frac{1}{\sqrt{5}}(i\psi_{210} + 2\psi_{211})[/tex]

What possible outcomes is possible if you do an energy measurement on the system in this state, and with what probability does this occur ?


Homework Equations


I know that the states [itex]\psi_{21-1}, \psi_{210}[/itex] and [itex]\psi_{211}[/itex] is given by the matrix [itex]H[/itex]:

[tex]\[ \left( \begin{array}{ccc}<br /> E_{2} + 2\gamma\hbar^{2} & 0 & 0 \\<br /> 0 & E_{2} + 2\gamma\hbar^{2} & 0 \\<br /> 0 & 0 & E_{2}\end{array} \right)\][/tex]

Don't know if I need to be telling more ?

The Attempt at a Solution


Well, I know the outcome has to be the two last states (In the order I wrote my states), which means: [itex]\psi_{210}[/itex] and [itex]\psi_{211}[/itex].
This means that I have to calculate the probability for those two, which means: [itex]P(E_{2} + 2\gamma\hbar^{2})[/itex] and [itex]P(E_{2})[/itex].

My problem is, that I'm not quite sure how to calculate that :/

My book says:

[tex]P(j) = \frac{N(j)}{N},[/tex]
but I have no idea how to make use of that in this case.

I know the answer should be: [itex]P(E_{2} + 2\gamma\hbar^{2}) = \frac{1}{5}[/itex] and [itex]P(E_{2}) = \frac{4}{5},[/itex]
but again, not sure how to do it.

So I was hoping someone could give me some pointers towards this, probably, easy question :)


Regards.
 
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I will use the bracket notation...

You are given a normalized wavefunction [itex]|\Psi\rangle[/itex]. So the probability of measuring a specific eigenstate [itex]|\psi_j\rangle[/itex] is just:

[tex]P(j) = \left|\langle\psi_j|\Psi\rangle\right|^2[/tex]

Each eigenstate corresponds to a specific energy. So you know the probability of measuring a specific energy.
 
Ahhh, ofc...
I think I have it now :)

Thank you very much.
 

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