Finding the projection of a Vector

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SUMMARY

The discussion centers on the projection of a vector, specifically addressing a potential error in the formula presented. The correct projection is identified as ##-\dfrac{15}{37}(i+6j)##, with emphasis on the negative sign in front of the fraction. Participants clarify the distinction between the vector unit ##\mathbf{i}## and the imaginary unit i, highlighting the importance of accuracy in vector notation. The conversation underscores the necessity of verifying calculations and understanding vector components in mathematical problems.

PREREQUISITES
  • Understanding of vector notation and components
  • Familiarity with vector projection formulas
  • Basic knowledge of mathematical operations involving vectors
  • Ability to differentiate between vector units and imaginary units
NEXT STEPS
  • Study vector projection techniques in linear algebra
  • Learn about vector operations in 3D space
  • Explore the differences between vector and imaginary units
  • Practice solving vector problems using software like MATLAB or Python
USEFUL FOR

Students studying linear algebra, mathematicians, and anyone involved in physics or engineering requiring a solid understanding of vector projections.

chwala
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Homework Statement
Kindly see attached.
Relevant Equations
vector knowledge
I am looking at this now; pretty straightforward as long as you are conversant with the formula: anyway i think there is a mistake on highlighted i.e
1689563985799.png
1689564008049.png
Ought to be

##-\dfrac{15}{37}(i+6j)##

just need a confirmation as at times i may miss to see something. If indeed its a mistake then its time to look for a better resource.
 
Last edited:
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##1(3) + 6(-2) = 3 - 12 = -9##

Note the negative sign out front of the fraction.

-Dan
 
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Maybe you are confusing a vector unit ##\mathbf{i}## with imaginary unit i.
 
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topsquark said:
##1(3) + 6(-2) = 3 - 12 = -9##

Note the negative sign out front of the fraction.

-Dan
but

##\vec u= -i+4j+3k##

aaaaaargh let me take a break...thanks man.
 
anuttarasammyak said:
Maybe you are confusing a vector unit ##\mathbf{i}## with imaginary unit i.
Actually, i was looking at the wrong question...you realise that i have posted a: question which is referenced to a totally different solution i.e b: solution.
 

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