Finding the Ratio of Initial Speed and Angular Speed for a Struck Snooker Ball

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Homework Help Overview

The problem involves a uniform snooker ball that is struck by a cue, leading to an initial linear speed and angular speed. The task is to find the ratio of these speeds in terms of the height at which the cue strikes the ball.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants express confusion regarding the interpretation of the problem statement, particularly the phrase about the cue tip's trajectory. There is discussion about whether the height h equals the radius r and the implications of ignoring friction on the ball's initial rotation.

Discussion Status

Participants are exploring different interpretations of the problem's wording. Some suggest that the problem may be poorly phrased, while others clarify that the cue's trajectory likely implies no side spin. Guidance has been offered in the form of interpretations, but no consensus has been reached.

Contextual Notes

There is uncertainty regarding the clarity of the problem statement and its implications for the ball's motion. Participants are questioning the assumptions made about the cue's trajectory and its effect on the ball's initial rotation.

JazzCarrot
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So, we're playing snooker...

Homework Statement



A (uniform) snooker ball of radius r, at rest on a table, is struck by a cue at a point a distance h above the table. Assume the cue tip is traveling horizontally, in a plane through the centre of the ball. As a result, the ball begins to move with an initial linear speed V0 and angular speed w0.

Consider the cue as acting with a large force F for a short time. Ignoring the effects of friction between the ball and the table for this time, find an expression for the ratio V0/w0 in terms of h.

Homework Equations



Once I've sussed the question, I can identify which.

The Attempt at a Solution



Well, I'm confused due to the sentence; "Assume the cue tip is traveling horizontally, in a plane through the centre of the ball". This to me means, that h = r? Therefore, if friction is to be ignored this time, the ball will not (initially) rotate?

If someone could clear this up, I'm sure I can crack on with the next few parts of the question.
 
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JazzCarrot said:
Well, I'm confused due to the sentence; "Assume the cue tip is traveling horizontally, in a plane through the centre of the ball". This to me means, that h = r? Therefore, if friction is to be ignored this time, the ball will not (initially) rotate?
I suspect that it's just a sloppily worded problem, and that the 'in a plane through the center of the ball' should be ignored. (Otherwise your interpretation is correct, but then the problem makes little sense.)

(This isn't from some textbook, I hope. If it is, give a reference.)
 


I would assume it means in a vertical plane through the centre of the ball. In other words, you are not putting any side spin on it.
 


Stonebridge said:
I would assume it means in a vertical plane through the centre of the ball. In other words, you are not putting any side spin on it.
Excellent. That's it.
 


I suspect that it's just a sloppily worded problem

Probably, my Mechanics Lecturer isn't the greatest at writing them.

I would assume it means in a vertical plane through the centre of the ball. In other words, you are not putting any side spin on it.

Awesome, I'll try it like that. Thanks!
 

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