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Angular Momentum Problem (from Giancoli)

  1. Aug 4, 2014 #1
    1. The problem statement, all variables and given/known data

    On a level billiards table a cue ball, initially at rest at point O on the table, is struck so that it leaves the cue stick with a center-of-mass speed v0 and a "reverse" spin of angular speed w0. A kinetic friction force acts on the ball as it initially skids across the table. Using conservation of angular momentum, find the critical angular speed, ωC, such that if ω0 = ωC, kinetic friction brings the ball to a complete stop.

    2. Relevant equations

    L = r x p , L = Iω , and L = spin angular momentum + orbital angular momentum

    3. The attempt at a solution

    using L = spin angular momentum + orbital angular momentum (derived earlier), L = (2/5mR2)ωC - mv0r, where r is the distance from the origin, O, and R is the radius of the billiards ball. L is constant because no net external torque acts on the ball after it is hit, so i can solver for ωC: ωC = 5v0r/2R2.

    I checked the solution in the solutions manual, and it is reduced to 5v0/2R. I do not know why r = R, or orbital angular momentum depends on the radius of the ball, rather than the distance from the origin.

    Thanks in advance.
     
  2. jcsd
  3. Aug 4, 2014 #2
    r = perpendicular distance from the origin
     
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