Finding the red planet's period using Kepler's third law

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In the figure the blue planet has a period of 1 year and an average distance from the sun of 1.73 x 1011 meters. If the average distance from the sun for the red planet is 1.39 x 1011 meters, what is its period to the nearest hundredth of a year?

So I thought maybe they through in the information on the blue planet to confuse me, so disregarding that information, I used the formula:

T=(2pi/square root of GM)*r^3/2
where G=6.67e-11 and M is the mass of the sun=2.0e30kg

Unfortunately, this isn't correct, and I don't see where I am supposed to incorporate the information about the blue planet with the red planet.
 

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Maybe you are not supposed to use the values for M and G in this problem. Just write the expressions of T for the two planets and eliminate [tex]\sqrt(GM)[/tex].
 
dalitwil said:
In the figure the blue planet has a period of 1 year and an average distance from the sun of 1.73 x 1011 meters. If the average distance from the sun for the red planet is 1.39 x 1011 meters, what is its period to the nearest hundredth of a year?

Did you learn Kepler's Law? All you need is a proportionality.
 
Right, the period T is proportional to r^3/2 (Kepler's 3rd law), but I am still unsure how to relate the two planets using this concept.
 
dalitwil said:
Right, the period T is proportional to r^3/2 (Kepler's 3rd law), but I am still unsure how to relate the two planets using this concept.

If

[tex]x^m \propto y^n[/tex]

then, if you have two systems that fit the proportionality:

[tex]\frac{x_1^m}{x_2^m}=\frac{y_1^n}{y_2^n}[/tex]

This applies to all values of m and n.

Proportionality just implies that there is some constant out front. If you have a test case with which to determine that constant, that's all you need.
 
T^2/a^3=const for all planets orbiting the same massive object.