- #1
thomas49th
- 655
- 0
Homework Statement
Find the set of values for x which
[tex]\frac{(x-3)^{2}}{x+1} < 2[/tex]
I turned this into
[tex]\frac{(x-7)(x-1)}{x+1} < 0 [/tex]
Now this implies that the critical angles are x = 7, 1 and -1 but how do I create the sets. I think I have to do somthing with sign change?
Thanks :)
EDIT: WHAT'S WRONG WITH MY LATEX??