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## Homework Statement

Find the set of values for x which

[tex]\frac{(x-3)^{2}}{x+1} < 2[/tex]

I turned this into

[tex]\frac{(x-7)(x-1)}{x+1} < 0 [/tex]

Now this implies that the critical angles are x = 7, 1 and -1 but how do I create the sets. I think I have to do somthing with sign change?

Thanks :)

EDIT: WHAT'S WRONG WITH MY LATEX??